28g^2=63

Solution for 28g^2=63 equation:

28g^2=63

We move all terms to the left:

28g^2-(63)=0

a = 28; b = 0; c = -63;
Δ = b2-4ac
Δ = 02-4·28·(-63)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*28}=\frac{-84}{56}
=-1+1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*28}=\frac{84}{56}
=1+1/2
$